From the question, we can deduce the folllowing:
Total amount = $5.40
Number of pennies = two times the number of quarters.
We have:
P = 2Q
Let's find the amount of each coin he has.
Let P represent the number of pennies
Let Q represent the number of quarters.
Where:
1 penny = $0.01
1 quarter = $0.25
We have the set of equations:
0.01P + 0.25Q = 5.40............................equation 1
P = 2Q.......................................................equation 2
Let's solve the system of equations using substitution method.
Substitute 2Q for P in equation 1:
0.01(2Q) + 0.25Q = 5.40
0.02Q + 0.25Q = 5.40
Combine like terms:
0.27Q = 5.40
Divide both sides by 0,27:
[tex]\begin{gathered} \frac{0.27Q}{0.27}=\frac{5.40}{0.27} \\ \\ Q=20 \end{gathered}[/tex]
Now, substitute 20 for Q in equation 2:
P = 2Q
P = 2(20)
P = 40
We have the solutions:
P = 40, Q = 20
Therefore, Ty has 40 pennies and 20 quarters.
ANSWER:
Quarters = 20
Pennies = 40
