Juan the trainer has two solo workout plans that he offers his clients: plan a and plan b, then the each of the workout plans are,
Plan a = a = 0.22 hours
Plan b = b = 0.66 hours
Juan the trainer has two solo workout plans that he offers his clients: plan a and plan b
On Friday there were 3 clients who did plan a and 5 who did plan b.
On Saturday there were 9 clients who did plan a and 7 who did plan b.
So,
We can write,
Friday can be expressed as: 3a + 5b
Saturday can be expressed as: 9a + 7b
Juan trained his Friday clients for a total of 6 hours and his Saturday clients for a total of 12 hours.
So, Total Time is,
Friday = 6 hours
Saturday = 12 hours
To find time for each session (A and B)
The question illustrates simultaneous equation and the equations are;
3a + 5b = 6 (Equation-1)
9a + 7b = 12 (Equation-2)
Multiply the first equation by 3
3(3a + 5b) = 3*6
9a+15b = 18 (Equation-3)
Subtract this from the first equation:
9a+15b = 18
9a + 7b = 12
--------------------------
15b-7b = 18-12
8b = 6
b = 6/18
b = 2/3
b = 0.66 hours
Substitute b value in equation-1,
3a + 5b = 6
3a + 5(2/3) = 6(2/3)
3a + 5*0.66 = 6*0.66
3a + 3.3 = 3.96
3a = 3.96-3.3
3a = 0.66
a = 0.66/3
a = 0.22 hours
Therefore,
Juan the trainer has two solo workout plans that he offers his clients: plan a and plan b, then the each of the workout plans are,
Plan a = a = 0.22 hours
Plan b = b = 0.66 hours.
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