The given expression is
[tex]9x+18[/tex]
To factor it, we will find the highest common factor of 9 and 18
Since the factors of 9 are all the numbers multiplying together and giving 9, then
[tex]\begin{gathered} 9\times1=9 \\ 3\times3=9 \end{gathered}[/tex]
The factors of 9 are 1, 3, 9
We will find the factors of 18 by the same way
[tex]\begin{gathered} 1\times18=18 \\ 2\times9=18 \\ 3\times6=18 \end{gathered}[/tex]
The factors of 18 are 1, 2, 3, 6, 9, 18
The common factors of 9 and 18 are 1, 3, 9
The greatest one is 9
Then the highest common factor of 9 and 18 is 9
Divide each term in the expression by 9
[tex]\begin{gathered} 9x+18= \\ \\ 9(\frac{9x}{9}+\frac{18}{9})= \\ \\ 9(x+2) \end{gathered}[/tex]
The correct expression is C [9(x + 2)]
