What is the eqation of the line parallel to the line 3x+6y=12 and passes through the point (4,-3)
step 1
Find the slope of the given line
3x+6y=12
isolate the variable y
6y=-3x+12
y=-(1/2)x+2
the slope is
m=-1/2
Remember that
If two lines are parallel, then their slopes are the same
so
the slope of the paralell line is
m=-1/2
step 2
Find the equation of the line in point slope form
y-y1=m(x-x1)
we have
m=-1/2
(x1,y1)=(4,-3)
substitute
y+3=-1/2(x-4)
y+3=-1/2x+2
