We have to solve the following expression:
[tex]-45b^{-2}\div15b^5\cdot4b^5[/tex]
We can rearrange the factors as:
[tex]\begin{gathered} -45b^{-2}\div15b^5\cdot4b^5 \\ \\ -\frac{45}{b^2}\cdot\frac{1}{15b^5}\cdot4b^5 \\ \\ -\frac{3\cdot15}{b^2}\cdot\frac{1}{15}\cdot4 \\ \\ -\frac{12}{b^2} \\ \\ -12b^{-2} \end{gathered}[/tex]
Answer: -12b^(-2)
