Question

rates of effusion are measured for 1 mole samples of two different gases, a and b, from identical containers at standard temperature. gas b effuses 3.16 times faster than gas a. gas a is ar. what could gas b be

Answer 1

The gas that could be identified as gas B is helium(He).

What is the rate of diffusion?

We know that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass of the gas. If we then have two masses of gas then we can write;

R1/R2 = √M2/M1

Given that;

R1 = rate of diffusion of gas 1

R2 = rate of diffusion of gas 2

M2 = molar mass of gas 2

M1 = molar mass of gas 1

We are told that Gas 2 diffuses 3.16 times faster than gas 1. We now know that;

1/3.16 = √M2/40

(1/3.16)^2 = M2/40

1/9.99= M2/40

40 = 9.99 M2

M2 = 40/9.99

M2 = 4

Learn more about diffusion:https://brainly.com/question/24746577

#SPJ1