SOLUTION
Write out the given linear equation
[tex]y+4x=6[/tex]For the first ordered pair,
[tex]\begin{gathered} (-1,\text{?)} \\ x=-1,y=\text{?} \end{gathered}[/tex]Substitute the value of x into the linear equation to find the value of y
[tex]\begin{gathered} y+4x=6 \\ y+4(-1)=6\ldots\text{.}\ldots(\text{expand the paranthesis )} \\ y-4=6\ldots\ldots(\text{add 4 to both sides )} \\ y-4+4=6+4 \\ y=10 \\ \text{The ordered pair is (-1,10)} \end{gathered}[/tex]a). Therefore For the first ordered pair, the missing coordinate y is 10
Similarly, for the second ordered-pair
[tex]\begin{gathered} (4,\text{?)} \\ x=4,y=\text{?} \end{gathered}[/tex]Substitute the value of x into the linear equation to obtain the value of y
[tex]\begin{gathered} y+4x=6 \\ y+4(4)=6 \\ \text{Expand the parenthesis} \\ y+16=6 \\ \text{subtract 16 from both sides } \\ y+16-16=6-16 \\ y=-10 \\ \text{Ordered pair=(4,-10)} \end{gathered}[/tex]b). Therefore for the second ordered pair, the missing coordinates y is -10