Question

I just had this problems solved with a tutor, and apparently the answer given was incorrect. Can you please help me resolve this problem?

Answer 1

Answer:

$HNO_{2(aq)}\text{ + H}_2O_{(l)}\text{ }\rightleftarrows\text{ NO}_{2(aq)}^-\text{ + H}_3O_{(aq)}^+$

Explanation:

Here, we want to write the acidic equilibrium equation for the given acid

What we have to do here is to write an equation in which the molecule is dissolved in water to give an oxonium ion and the corresponding conjugate

We have that as follows;

$HNO_{2(aq)}\text{ + H}_2O_{(l)}\text{ }\rightleftarrows\text{ NO}_{2(aq)}^-\text{ + H}_3O_{(aq)}^+$