Question

Elizabeth brought a box of donuts to share. There are two-dozen (24) donuts in the box, all identical in size, shape, and color. Four are jelly-filled, 9 are lemon-filled,and 11 are custard-filled. You randomly select one donut, eat it, and select another donut. Find the probability of selecting two jelly-filled donuts in a row.(Type an integer or a simplified fraction.)

Answer 1

select one donut

$\frac{4}{24}=\frac{1}{6}$

select another donut

$\frac{3}{23}$

then the probability to select two jelly-filled donuts:

$\frac{1}{6}+\frac{3}{23}=\frac{23}{138}+\frac{18}{138}=\frac{23+18}{138}=\frac{41}{138}$

answer: 41/138