Question

f(n)=41-5ncomplete the recruisve formula of f(n)f(1)=f(n)=f(n-1)+

Answer 1

$\begin{gathered} f\mleft(1\mright)=36 \\ f(n)=f(n-1)-5 \end{gathered}$

Explanation

Step 1

Let

$f(n)=41-5n$

a) f(1)

replace the valur for n

$\begin{gathered} f(n)=41-50 \\ f(1)=41-5(1)=41-5=36 \\ f(1)=36 \end{gathered}$

Step 2

find f(2) and f(3)

$\begin{gathered} f(2)=41-5(2)=41-10=31 \\ f(2)=31 \\ f(3)=41-5(3)=41-15=26 \end{gathered}$

then, we have

$\begin{gathered} f(1)=36 \\ f(2)=31 \\ f(3)=26 \end{gathered}$

As you can see, the next term is the previous one minus 5,in math terms

$f(n)=f(n-1)-5$