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EXPLANATION

If I=r√2, replacing terms:

[tex]r\sqrt[]{2}=2r\sin \frac{180}{n}[/tex]

Dividing both sides by 2r:

[tex]\frac{r\cdot\sqrt[]{2}}{2r}=\sin \frac{180}{n}[/tex]

Simplifying:

[tex]\frac{\sqrt[]{2}}{2}=\sin \frac{180}{n}[/tex]

Applying sin-1 to both sides:

[tex]\sin ^{-1}\frac{\sqrt[]{2}}{2}=\frac{180}{n}[/tex]

Multiplying both sides by n:

[tex]n\cdot\sin ^{-1}\frac{\sqrt[]{2}}{2}=180[/tex]

Dividing both sides by sin-1 (sqrt(2)/2):

[tex]n=\frac{180}{\sin ^{-1}\frac{\sqrt[]{2}}{2}}[/tex]

Solving the argument:

[tex]n=\frac{180}{45}[/tex]

Simplifying:

[tex]n=4[/tex]

The answer is n=4

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