Question

If 58% of the people at a certain conference are doctors, 44% are men, and 43% are male doctors, what is the probability that a person selected at random atthis conference is a doctor or man (or both)?Write your answer as a decimal (not as a percentage).

Answer 1

Given data:

Assume the following events:

Event A = person is a doctor

Event B = person is a man

P(A) = 58% are doctors

P(B) = 44% are men

P(A and B) = 43% are male doctors

Find: probability that a random person is a doctor or a man or both (A or B)

Solution:

$\begin{gathered} P(\text{A or B)}=P(A)+P(B)-P(A\text{ and B)} \\ P(A\text{ or B)}=0.58+0.44-0.43 \\ P(A\text{ or B)}=0.59 \end{gathered}$

Answer: The probability that a person selected at random at

this conference is a doctor or man (or both) is 59%.