Respuesta :

Explanation

We are asked to simplify

[tex]\int_{-1.2}^{0.8}\frac{tanx}{x+9}dx,\text{ n=3}[/tex]

To solve this, we will have

So that

[tex]\Delta x=\frac{0.8-(-1.2)}{3}=\frac{2}{3}[/tex]

next, we will divide the intervals into 3

[tex]\begin{gathered} We\text{ will divide \lbrack-1.2,0.8\rbrack into 3} \\ \end{gathered}[/tex]

[tex]\begin{gathered} \text{ } \\ so\text{ we have} \\ -\frac{6}{5},-\frac{8}{15},\frac{2}{15},\frac{4}{5} \\ \end{gathered}[/tex]

Thus, we will have

So we will have

[tex]-0.111597[/tex]

So the answer is -0.1116

Ver imagen JazzlynnL21714
Ver imagen JazzlynnL21714
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