Question

Which shows the following expression after the negative exponents have been eliminated?ХО, у 0+у? бувکرولاу? хуб.

Answer 1

We are given the following expression

$\frac{xy^{-6}}{x^{-4}y^2}$

Recall the negative exponent rule given by

$a^{-x}=\frac{1}{a^x}\: or\: \frac{1}{a^{-x}}=a^x$

Let us apply the above rule to the given expression

$\frac{xy^{-6}}{x^{-4}y^2}=\frac{x}{x^{-4}y^2y^6}=\frac{xx^4}{^{}y^2y^6}$

Therefore, the expression after the negative exponents have been eliminated is

$\frac{xx^4}{^{}y^2y^6}$

The 2nd option is the correct answer.