The sum of six times a number and 7 more than the number can be represented as 6x + (x+7)
Is the same as the difference between -20 and twice the number, which can be represented as -20 - 2x
Now, the equation would be :
[tex]6x\text{ +(x+7)=-20-2x}[/tex]We need to solve for x:
[tex]6x\text{ +x+7=-20-2x}[/tex][tex]7x+7=-20-2x[/tex]Add both sides 2x
[tex]7x+7+2x=-20-2x+2x[/tex][tex]9x+7=-20[/tex]Subtract both sides by 7:
[tex]9x+7-7=-20-7[/tex][tex]9x=-27[/tex]Divide both sides by 9:
[tex]\frac{9x}{9}=\frac{-27}{9}[/tex][tex]x=-3[/tex]