We are given the following information
Deposited amount = $4000
Interest rate = 4.5% = 0.045
Number of years = t = 6
Compounding = continuously
We can use the following formula for continuous compounding
[tex]A=P\cdot e^{r\cdot t}[/tex]Let us substitute the given values
[tex]\begin{gathered} A=P\cdot e^{r\cdot t} \\ A=4000\cdot e^{0.045\cdot6} \\ A=4000\cdot e^{0.27} \\ A=4000\cdot1.3099 \\ A=\$5239.6 \end{gathered}[/tex]Therefore, the value after 6 years will be $5239.6