Question

A spaceship moving with an initial velocity of 58.0 meters/second experiences a uniform acceleration and attains a final velocity of 153 meters/second. What distance has the spaceship covered after 12.0 seconds? 6.96 × 102 meters 1.27 × 103 meters 5.70 × 102 meters 1.26 × 102 meters 6.28 × 102 meters

Answer 1

Given

u→Initial velocity of the spaceship=58ms

v→after t= 12s ,Final velocity of the spaceship =153ms

The spaceship moving with uniform acceleration

s→The distance covered in t s=12(u+v)×t=12(58+153)×12=1266m