Determine the equation of line passing through the point (6,8) and (-2,4).
[tex]\begin{gathered} y-8=\frac{4-8}{-2-6}(x-6) \\ y-8=\frac{4}{-8}(x-6) \\ y-8=-\frac{x}{2}-\frac{1}{2}\cdot(-6) \\ y=\frac{-x}{2}+3+8 \\ y=\frac{-x}{2}+11 \end{gathered}[/tex]So equation of line is y=-x/2+11.