The midpoint (x,y) of a line segment with point (x1,y1) and (x2,y2) is given below as
[tex](x,y)=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]Where the given values are
[tex]\begin{gathered} (17,-11) \\ x_1=17,y_1=-11 \\ (-14,-16) \\ x_2=-14,y_2=-16 \end{gathered}[/tex]By substituting the values in the formula above
[tex]\begin{gathered} (x,y)=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}) \\ (x,y)=(\frac{17+(-14)}{2},(\frac{-11+(-16)}{2}) \\ (x,y)=(\frac{17-14}{2},\frac{-11-16}{2}) \\ (x,y)=(\frac{3}{2},-\frac{27}{2}) \end{gathered}[/tex]Hence,
The final answer is OPTION D
