0.913 A
Explanation
the poweris given by
[tex]P=I^2R[/tex]so
Step 1
Let
[tex]\begin{gathered} I=I \\ P=100\text{ watts} \\ \text{resistance}=120\text{ ohm} \end{gathered}[/tex]b) now replace
[tex]\begin{gathered} P=I^2R \\ 100=I^2\cdot120 \\ \text{divide boths sides by 120} \\ \frac{100}{120}=\frac{I^2\cdot120}{120} \\ 0.8333=I^2 \\ \text{square root in both sides} \\ \sqrt{0.8333}=\sqrt{I^2} \\ 0.91287=I \\ \text{rounded} \\ I=0.913\text{ Amperes} \end{gathered}[/tex]therefore, the answeris
0.913 A
I hope this helps you