We have the quadratic equation:
[tex]y=3x^2+60x-150[/tex]And want to write in the vertex form by completing the square, so we take the coefficient of squared x as a factor:
[tex]\begin{gathered} y=3x^2+60x-150 \\ y=3(x^2+20x-50) \end{gathered}[/tex]Take the coefficient of x and divided by 2 and the calculate the square, and add and substract the result into the parenthesys, so:
[tex]\begin{gathered} y=3(x^2+20x-50+(\frac{20}{2})^2-(\frac{20}{2})^2) \\ y=3(x^2+20x+100-50-100) \\ y=3(x^2+20x+100-150) \\ y=3(x^2+20x+100)-3\cdot150 \\ y=3(x^2+20x+100)-450 \end{gathered}[/tex]Now, write the parenthesys as a binomial squared:
[tex]y=3(x+10)^2-450[/tex]The option a) is the correct answer.