Given: Sinister Stan sole 3 3/4 oz of slime from Messy Molly and another 2 3/5 oz of slime from Rude Ralph.
Total slime required for his evil plans=6 3/8.
Therefore, slime requried to achive his plan is given by:
[tex]\begin{gathered} 6\frac{3}{8}-(3\frac{3}{4}+2\frac{3}{5})=\frac{51}{3}-(\frac{15}{4}+\frac{13}{5}) \\ =\frac{51}{8}-(\frac{75}{20}+\frac{52}{20}) \\ =\frac{51}{8}-(\frac{127}{20}) \\ =\frac{510}{80}-\frac{508}{80} \\ =\frac{2}{80} \\ =\frac{1}{40} \end{gathered}[/tex]Thus, the slime requried to achieve the evil plan is:
[tex]\frac{1}{40}[/tex]