Hello I need help with question 7! I will give you a great rating! Please help, I’m not sure how to do this. Also this is not a quiz this is practice

To find:
The value of x and y.
Solution:
In the given triangle, the sine value of the angle is:
[tex]\begin{gathered} \sin(30)=\frac{opposite}{hypotenuse} \\ \frac{1}{2}=\frac{4}{x} \\ x=8 \end{gathered}[/tex]The cosine value of the angle is:
[tex]\begin{gathered} \tan30=\frac{opposite}{adjacent} \\ \frac{1}{\sqrt{3}}=\frac{4}{y} \\ y=4\sqrt{3} \end{gathered}[/tex]Thus, the values are:
[tex]x=8,y=4\sqrt{3}[/tex]