Respuesta :

Step 1

Given;

[tex]\begin{gathered} A\text{ deposit of \$100 each month} \\ 7\text{\% interest com}pounded\text{ }monthly \end{gathered}[/tex]

Step 2

State the formula to simplify the problem

[tex]=A(\frac{(1+i)^n-1}{i})[/tex][tex]\begin{gathered} A=\text{ \$100} \\ i\text{ = }\frac{0.07}{12}=\frac{7}{1200} \\ n=\text{ 30 years}=\text{ 30 x }12=\text{ 360 months} \end{gathered}[/tex]

Hence,

[tex]\begin{gathered} =\frac{100((1+\frac{7}{1200})^{360}-1)}{\frac{7}{1200}} \\ =\text{\$}121997.0966 \\ \approx\text{\$}121997.1 \end{gathered}[/tex]

Hence, the account will have $121997.1 in 30 years

Step 3

Find how much total money will be put in the account.

[tex]=\text{ 100 }\times\text{ 30 }\times12\text{ =\$}36000[/tex]

The total amount of money that will be put into the account = $36000

Step 4

Find out how much total interest you will earn

[tex]\begin{gathered} Interest\text{ = amount in 30 years - total money} \\ \text{Interest = }121997.1-36000 \\ \text{Interest = \$}85997.1 \end{gathered}[/tex]

Total interest you will earn = $85997.1

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