Experiment ONE:
We can model the equation linearly. The linear form is:
[tex]y=mx+b[/tex]Where
m is the slope (or, rate)
b is the y-intercept (or, initial value)
Given, the initial value is "50", we can say b = 50.
The mold triples with each observation. So, the rate (m) is 3.
Thus, the equation to model this situation is:
[tex]y=3x+50[/tex]Experiment TWO:
We can also model this situation linearly.
This situation is an easier one. The number of molds increase by 8 with each observation. So, the rate (m) is "8".
The initial value (b) is "12".
So, we can model the equation:
[tex]y=8x+12[/tex]To find out if mold on muffin will ever be greater than mold on bread, we can write:
[tex]8x+12>3x+50[/tex]Let's solve for x:
[tex]\begin{gathered} 8x+12>3x+50 \\ 8x-3x>50-12 \\ 5x>38 \\ x>\frac{38}{5} \\ x>7\frac{3}{5} \end{gathered}[/tex]So, from 8 observation onwards, the amount of mold on the muffin will be greater than the amount of mold on the bread.