Question

For the circuit shown, determine the current in the middle wire going through the ammeter, A .

Answer 1

Given:

v1 = 6 v

R1 = 0 ohm

v2 = 12 v

R2 = 4 ohm

To find:

The current going through the ammeter.

Explanation:

The current I going through ammeter will be the addition of current I1 and current I2.

Thus,

$\begin{gathered} I=I_1+I_2 \\ \\ I=\frac{V_1}{R1}+\frac{V_2}{R_2} \end{gathered}$

Substitute the values in the above equation, we get:

$\begin{gathered} I=\frac{6\text{ v}}{8\text{ }\Omega}+\frac{12\text{ v}}{4\text{ }\Omega} \\ \\ I=3.75\text{ A} \end{gathered}$

Final Answer:

The current passing through the ammeter is 3.75 A.