We must have in mind the surface of a sphere that is given by
[tex]S_a=4\pi r^2[/tex]When the radius of the sphere triples, the new radius becomes r1=3r. So, the new surface area of a sphere is
[tex]S_{a1}=4\pi(3r)^2=9(4\pi r^2)=36\pi r^2[/tex]As we can see, the surface area is multiplied by 9. The correct answer is D.