Question

what is delta g for the reaction at body temperature (37 degree celsius) if the concentration of a is 1.8m and b 0.55m

Answer 1

At 37 degrees Celsius, the reaction's G is equal to -3053.6066 kJ mol-1.

calculation:-

Using the formula below, we can calculate the value of G.

G = -RT*Ink

where; R (gas constant)=8.314K J/Kmol.

37 + 273 = 310 k, where T is the reaction's temperature.

K = Ratio of Convergence = 1.8/ 0.55 = 3.27

Put values in the equation above.

G equals -3053.6066 kJ per mole.

Consequently, we may say that the G for the reaction at 37 °C is - 3053.6066 kJ mol-1.

How does one calculate Delta G given a temperature and k?

The formula G°=RTlnK relates °G to °K. Products are preferred over reactants in equilibrium if G° 0, K > 1, and. At equilibrium, reactants are preferred over products if G° > 0, K 1.

To know more about gas constant visit:-

https://brainly.com/question/24281105

#SPJ4