Respuesta :

Given:

[tex]23^o10^{\prime}44^{\doubleprime}[/tex]

Here degrees =23, minutes =10, and seconds =44.

We know that

[tex]Decimal\text{ degr}ees\text{ = Degr}ees+(\frac{\min utes}{60})+(\frac{\text{seconds}}{3600})[/tex]

Substitute degrees =23, minutes =10, and seconds =44, we get

[tex]=23+\frac{10}{60}+\frac{44}{3600}[/tex]

[tex]=23+0.1667+0.0122[/tex]

[tex]=23.1789[/tex]

Hence the decimal place is

[tex]23^o10^{\prime}44^{\doubleprime}=23.1789^o[/tex]

ACCESS MORE
EDU ACCESS
Universidad de Mexico