Given:
Large drink cost $ 2.75.
Let x be the number of large drinks.
Let y be the number of medium drinks and it cost $2.15 each.
A restaurant sold 52 drinks yesterday and took in a total of $131.60.
The equations are,
[tex]\begin{gathered} x+y=52\ldots\ldots\ldots.....\ldots\ldots\ldots.....(1) \\ 2.75x+2.15y=131.60\ldots.\ldots..\ldots\ldots\ldots\text{.}(2) \end{gathered}[/tex]Solve the equations,
From equation 1)
[tex]\begin{gathered} x+y=52 \\ x=52-y \\ \text{Put it in equation 2)} \\ 2.75(52-y)+2.15y=131.60 \\ 143-2.75y+2.15y=131.60 \\ 143-131.60=0.6y \\ 11.4=0.6y \\ y=\frac{11.4}{0.6} \\ y=19 \end{gathered}[/tex]Put the value of y in equation 1)
[tex]\begin{gathered} x+y=52 \\ x+19=52 \\ x=52-19 \\ x=33 \end{gathered}[/tex]Answer: The number of medium drink sells are y = 19.