Guided practiceTopic: Chords and Arcs Geometry BA. 50B. 18C. 36D. 25

We know that the chord is 25 units long.
Also, according to the image, side 18 and half of the given chord from a right triangle. Let's find the hypothenuse with Pythagorean's Theorem.
[tex]\begin{gathered} r^2=18^2+25^2 \\ r=\sqrt[]{324+625}=\sqrt[]{949} \end{gathered}[/tex]Now, we use Pythagorean's theorem to find half of the chord x.
[tex]\begin{gathered} (\sqrt[]{949})^2=(\frac{x}{2})^2+18^2 \\ 949-324=(\frac{x}{2})^2 \\ 625=(\frac{x}{2})^2 \\ \frac{x}{2}=\sqrt[]{625}=25 \\ x=2\cdot25=50 \end{gathered}[/tex]