a) To solve this equation we are going to use inverse operations as addition and subtraction are inverse operations, also multiplication and division are inverse operations, so:
7x-15=1
7x=1+15
7x=16
x=16/7
b)
[tex]\begin{gathered} \frac{x+2}{4}=-2 \\ x+2=-2(4) \\ x+2=-8 \\ x=-8-2 \\ x=-10 \end{gathered}[/tex]
c)
[tex]\begin{gathered} -\frac{3}{5}x+2=7 \\ -\frac{3}{5}x=7-2 \\ -\frac{3}{5}x=5 \\ -3x=5(5) \\ x=-\frac{25}{3} \end{gathered}[/tex]
