Respuesta :

Answer: P(z>1.33) = 0.0918

Explanation:

On a normal curve, the areas are to the left. Thus.

P(z>1.33) = 1 - P(z < 1.33)

From the normal distribution table, the probability value corresponding to a z score 1.33 is 0.9082

P(z>1.33) = 1 - 0.9082

P(z>1.33) = 0.0918

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