Respuesta :

From the question,

We are to factorize

[tex]33x^2+2x-3[/tex]

This is done as follows

[tex]\begin{gathered} 33x^2+2x-3 \\ =33x^2+11x-9x-3 \end{gathered}[/tex]

This is further factorized as

[tex]\begin{gathered} 33x^2+11x-9x-3 \\ =11x(3x+1)-3(3x+1) \\ =(3x+1)(11x-3) \end{gathered}[/tex]

Therefore, we have

[tex]\begin{gathered} 33x^2+2x-3 \\ =(3x+1)(11x-3) \end{gathered}[/tex]

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