Question

In circle Q with the measure of minor arc ⌢=60∘,PR⌢ =60 ∘ , find m∠PSR.

Answer 1

The measure of arc PR is 60 degree means angle subtend by arc PR at center is 60.

So measure of angle PQR is 60.

The relation between angle PQR and angle PSR is,

$\angle PSR=\frac{1}{2}\angle PQR$

Determine the measure of angle PSR.

$\begin{gathered} \angle PSR=\frac{1}{2}\cdot60 \\ =30 \end{gathered}$

So answer is,

$\angle PSR=30$