Given
Find
the value of x
Explanation
as we know when two secants intersect in the exterior circle , then the product of measure of one segment and its external segment is equal to the product of the measure of other secant and its external segment.
so ,
[tex]\begin{gathered} AC\times BC=CE\times CD \\ (21+x)\times x=(14+x+1)(x+1) \\ 21x+x^2=(15+x)(x+1) \\ 21x+x^2=15x+15+x^2+x \\ 5x=15 \\ x=3 \end{gathered}[/tex]
Final Answer
Hence , the value of x is 3
