Question

Vector v has an initial point at (7, 6) and a terminal point at (−11, 16). What is negative one half times vector v question mark

Answer 1

Answer:

The initial point of the vector is

$\begin{gathered} (7,6) \\ (x_1,y_1) \end{gathered}$

The terminal point of a vector is

$\begin{gathered} (-11,16) \\ (x_2,y_2) \end{gathered}$

Concept:

$v=(x_2-x_1),(y_2-y_1)$

By substituting the values, we will have

$\begin{gathered} v=(x_2-x_1),(y_2-y_1) \\ v=(-11-7),(16-6) \\ v=(-18,10) \end{gathered}$

We are asked to evaluate

$-\frac{1}{2}v$$\begin{gathered} -\frac{1}{2}v=-\frac{1}{2}(-18,10) \\ =-\frac{1}{2}\times-18,-\frac{1}{2}\times10 \\ =\frac{18}{2},-\frac{10}{2} \\ =(9,-5) \end{gathered}$

Hence,

The final answer is

$(9,-5)$

The FIRST OPTION is the right answer