Question

One spring day, Hakeem noted the time of day and the temperature, in degrees Fahrenheit. His findings are as follows: At 6 a.m., the temperature was 58° F. For the next 3 hours, the temperature rose 3° per hour. For the next 2 hours, it rose 4° per hour. The temperature then stayed steady until 6 p.m. For the next 3 hours, the temperature dropped 3° per hour. The temperature then dropped steadily until the temperature was 62° at midnight. On the set of axes below, graph Hakeem's data.

Answer 1

Answer:

Explanation:

The first thing we know is that the temperature at 6 am is 58° F. Therefore, we mark (6 am, 58 ° F on the graph.

The next thing we are told is that for the next three hours ( until 6 am + 3 = 9 am), the temperature rises 3 ° F per hour. This means by 9 am, the temperature is 58 ° F + 3 * 3 ° F = 67 ° F. And so we mark ( 9 am, 67 ° F).

Afterwards, for the next two hours ( until 9 am + 2 = 11 am ), the temperature rises at a rate of 4 ° F per hour. Meaning by 11 am, the temperature is 67 ° F + 4 * 2 = 75 ° F.

Therefore, we mark (11 am, 75° F).

Next, we are told that the temperature remains steady (does not change) until 6 pm. Meaning, the temperature at 6 pm is also 75° F. So we mark ( 6 pm, 75° F).

After 6 pm, the temperature drops at a rate of 3° F per hour for the next 3 hours ( until 6 pm + 3 = 9 pm ). Meaning, the temperature at 9 pm is 75 - 3 *3 = 66° F. Therefore, we mark ( 9