Please answer last one, full sentence with either A. The horizontal or oblique asymptote is __Or b. There is no horizontal

Given:
[tex]F(x)=\frac{x^{2}-11x-12}{x+6}[/tex]To find:
The horizontal asymptote or slant asymptote.
Explanation:
Dividing the polynomial we get,
[tex]F(x)=x-17+\frac{90}{x+6}[/tex]If x approaches infinity, then the above rational term becomes zero.
So, we will get
[tex]y=x-17[/tex]As we know,
An oblique (or slant) asymptote is a slant line that the function approaches as x approaches plus or minus infinity.
Therefore, the oblique asymptote is,
[tex]y=x-17[/tex]Final answer:
The oblique asymptote is,
[tex]y=x-17[/tex]