Respuesta :

Given the Complex Number:

[tex]z=1-i\sqrt{3}[/tex]

You can identify that it is written in Rectangular Form:

[tex]z=x+yi[/tex]

By definition, the coordinates in Rectangular Form are:

[tex](x,y)[/tex]

And in Polar Form:

[tex](r,\theta)[/tex]

In this case, you can identify that:

[tex]\begin{gathered} x=1 \\ y=\sqrt{3} \end{gathered}[/tex]

In order to convert them to Polar Form, you need to use these formulas:

[tex]\begin{gathered} x=r\cdot cos\theta \\ y=r\cdot sin\theta \end{gathered}[/tex]

Use this formula to find "r":

[tex]r=\sqrt{x^2+y^2}[/tex]

Then, this is:

[tex]r=\sqrt{1^2+(\sqrt{3})^2}=2[/tex]

You need to find the angle. You can use this formula:

[tex]\theta=tan^{-1}(\frac{y}{x})[/tex]

Therefore the angle is:

[tex]\theta=tan^{-1}(-\sqrt{3})+360\text{ \degree}[/tex]

[tex]\theta=300°[/tex]

Then:

[tex]z=2cos300\text{\degree}+2isin300\text{\degree}[/tex]

Hence, the answer is: Last option.

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