Remember the definition of the sine and the cosine of an angle in a right triangle:
[tex]\begin{gathered} \cos (\theta)=\frac{\text{Side adjacent to }\theta}{\text{Hypotenuse}} \\ \\ \sin (\theta)=\frac{\text{Side opposite to }\theta}{\text{ Hypotenuse}} \end{gathered}[/tex]
In the given triangle, the length of the hypotenuse is 5.
The side opposite to xº has a length of 3, then:
[tex]\sin (xº)=\frac{3}{5}[/tex]
The side adjacent to yº has a length of 3, then:
[tex]\cos (yº)=\frac{3}{5}[/tex]
As we can see, both cos(yº) and sin(xº) have the same value: 3/5.
Therefore, the correct choice is option 1:
The ratios are both identical (3/5 and 3/5).