Question

Find the equation of the line with slope m=1/5 that contains the point (-10,-5)

Answer 1

The point-slop form for a line is

$y-y_0=m(x-x_0),$

so, we only need to subsitute and solve for y or put it in the general form

$\begin{gathered} y-(-5)=\frac{1}{5}(x-(-10))_{} \\ y+5=\frac{1}{5}x+2 \\ y=\frac{1}{5}x-3 \end{gathered}$

Another way to write this equation is

$\begin{gathered} y=\frac{1}{5}x-3 \\ y+3=\frac{1}{5}x \\ 5y+15=x \\ x-5y-15=0 \end{gathered}$