Let the formula be for time in seconds
Thus, we have:
[tex]T(t)=T_a+(T_0-T_a)e^{-kt}[/tex]T_a would be the freezer temperature, 4
T_0 would be the initial temp, which is 73
t is the time [9 minutes afterwards, t = 9]
k is 0.05
Substituting, we get:
[tex]\begin{gathered} T(t)=T_a+(T_0-T_a)e^{-kt} \\ T(9)=4_{}+(73-4_{})e^{-(0.05)(9)} \\ T(9)=4+69e^{-0.45} \\ T(9)\approx48 \end{gathered}[/tex]To nearest degree Fahrenheight, T = 48 degrees F
