The equation given,
[tex]x^2+8x=4[/tex]
Rearranging,
[tex]x^2+8x-4=0[/tex]
Comparing to general form of a quadratic, we have:
[tex]\begin{gathered} a=1 \\ b=8 \\ c=-4 \end{gathered}[/tex]
Using the quadratic formula, we can find x.
[tex]\begin{gathered} x=\frac{-b\pm\sqrt[\square]{b^2-4ac}}{2a} \\ x=\frac{-8\pm\sqrt[\square]{(8)^2-4(1)(-4)}}{2(1)} \\ x=\frac{-8\pm\sqrt[\square]{80}}{2} \\ x=\frac{-8\pm4\sqrt[]{5}}{2} \\ x=-4\pm2\sqrt[\square]{5} \end{gathered}[/tex]
Answer
First answer choice
