Here is a graph of the equation 2y - x = 1.Are the points (0, 1/2) and (-7, -3) solutions to the equation? Explain how you know.

Given the graph of the equation:
[tex]2y-x=1[/tex]we will check if the points (0, 1/2) and (-7, -3) solutions to the equation
So, we will substitute the points into the equation
The first point (0, 1/2)
Substitute with x = 0, and y = 1/2
so,
[tex]LHS=2\cdot\frac{1}{2}-0=1=R\mathrm{}H\mathrm{}S[/tex]So, the point (0, 1/2) is a solution to the equation and as shown in the figure the line passes through the point which is the y-intercept
The second point (-7, -3)
Substitue with x = -7, and y = -3
so,
[tex]LHS=2\cdot-3-(-7)=-6+7=1=R.H.S[/tex]So, the point (-7, -3) is a solution to the equation.