Respuesta :

Given the graph of the equation:

[tex]2y-x=1[/tex]

we will check if the points (0, 1/2) and (-7, -3) solutions to the equation

So, we will substitute the points into the equation

The first point (0, 1/2)

Substitute with x = 0, and y = 1/2

so,

[tex]LHS=2\cdot\frac{1}{2}-0=1=R\mathrm{}H\mathrm{}S[/tex]

So, the point (0, 1/2) is a solution to the equation and as shown in the figure the line passes through the point which is the y-intercept

The second point (-7, -3)

Substitue with x = -7, and y = -3

so,

[tex]LHS=2\cdot-3-(-7)=-6+7=1=R.H.S[/tex]

So, the point (-7, -3) is a solution to the equation.

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