Question

how to solve 3[x+1]>-6 writing it in interval notations?

Answer 1

$3(x+1)>-6$

first solve for x

$\begin{gathered} x+1>-\frac{6}{3} \\ \\ x+1>-2 \\ x>-2-1 \\ x>-3 \end{gathered}$

This tells us that the values ​​that x can take must be greater than -3

so the interval notation is

$(-3,\infty)$

because these numbers are greater than -3 not including it