Respuesta :

Area of figure = Area of triangule + area of paralelogram

Area of triangule (At):

[tex]A_t=\frac{b\cdot h}{2},\text{ b = base and h = height}[/tex][tex]\begin{gathered} A_t=\frac{7.2\cdot3.1}{2} \\ A_t=\frac{22.32}{2}=11.16ft^2 \end{gathered}[/tex]

Area of paralelogram (Ap):

[tex]\begin{gathered} A_p=b\cdot h \\ A_p=7.2\cdot5 \\ A_p=36ft^2 \end{gathered}[/tex]

Area figure = At + Ap = 11.16+36

Area figure = 47.16 ft²

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