Answer: 0.7995 or 79.95%
Given:
X~N(23.4, 6.64)
Where:
mean = 23.4
standard deviation = 6.64
First, let us find the z-score using the formula:
[tex]z=\frac{x-\mu}{\sigma}[/tex][tex]z=\frac{29-23.4}{6.64}=0.84[/tex]Now, we need to look at the table and find the value of 0.8 under 0.04.
And here, we get .7995.
Therefore, the probability that the speed of a car is at most 29 is 0.7995 or 79.95%