The work done in joules if the gas expands is zero.
The magnitude of work done when a gas expands is equal to the product of the pressure times the change in the volume of the gas. By definition, we can say that, one joule work done is done when a force of one newton is used to move an object to one meter.
For a gas transformation at constant temperature, if the pressure p is constant then the work done is equal to ;
W= p Δv
Δv = change in volume of the gas.
Δv= 5.8L- 1.7L (Given in question)
= 4.1 L = 4.1 * 10⁻³ m³
a) When the gas expands in vacuum, the pressure is zero: p=0 atm, so the work done is zero:
W= p Δv
=(0)(4.1)
= 0 joules
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