Question

For which inequality would x = 8 not be a solution?72 ÷ x ≥ 49 x - 5 < 100x + 4 ≤ 104 x + 3 > 0

Answer 1

$x+4\leq10$

1) In this question, to solve it algebraically, we need to plug it in and verify each one.

2) So, let's do it by plugging it into that already:

$\begin{gathered} 71\div(8)\ge4\Rightarrow9\ge4\:True! \\ 9(8)-5<100\Rightarrow72-5<100\Rightarrow67<100\:True! \\ 8+4\leq10\Rightarrow12\leq10\:False! \\ 4(8)+3>0\Rightarrow35>0\:True! \end{gathered}$

Note that the only one that does not verify,i.e. it's a false one is the answer.

2) Thus, the answer is:

$x+4\leq10$